Optimal. Leaf size=181 \[ \frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac{f^3 p \log \left (d+e x^n\right )}{3 g}-\frac{e f^2 n p x^{n+1} \, _2F_1\left (1,1+\frac{1}{n};2+\frac{1}{n};-\frac{e x^n}{d}\right )}{d (n+1)}-\frac{e f g n p x^{n+2} \, _2F_1\left (1,\frac{n+2}{n};2 \left (1+\frac{1}{n}\right );-\frac{e x^n}{d}\right )}{d (n+2)}-\frac{e g^2 n p x^{n+3} \, _2F_1\left (1,\frac{n+3}{n};2+\frac{3}{n};-\frac{e x^n}{d}\right )}{3 d (n+3)} \]
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Rubi [A] time = 0.176117, antiderivative size = 181, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 4, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {2463, 1844, 260, 364} \[ \frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac{f^3 p \log \left (d+e x^n\right )}{3 g}-\frac{e f^2 n p x^{n+1} \, _2F_1\left (1,1+\frac{1}{n};2+\frac{1}{n};-\frac{e x^n}{d}\right )}{d (n+1)}-\frac{e f g n p x^{n+2} \, _2F_1\left (1,\frac{n+2}{n};2 \left (1+\frac{1}{n}\right );-\frac{e x^n}{d}\right )}{d (n+2)}-\frac{e g^2 n p x^{n+3} \, _2F_1\left (1,\frac{n+3}{n};2+\frac{3}{n};-\frac{e x^n}{d}\right )}{3 d (n+3)} \]
Antiderivative was successfully verified.
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Rule 2463
Rule 1844
Rule 260
Rule 364
Rubi steps
\begin{align*} \int (f+g x)^2 \log \left (c \left (d+e x^n\right )^p\right ) \, dx &=\frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac{(e n p) \int \frac{x^{-1+n} (f+g x)^3}{d+e x^n} \, dx}{3 g}\\ &=\frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\frac{(e n p) \int \left (\frac{f^3 x^{-1+n}}{d+e x^n}+\frac{3 f^2 g x^n}{d+e x^n}+\frac{3 f g^2 x^{1+n}}{d+e x^n}+\frac{g^3 x^{2+n}}{d+e x^n}\right ) \, dx}{3 g}\\ &=\frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}-\left (e f^2 n p\right ) \int \frac{x^n}{d+e x^n} \, dx-\frac{\left (e f^3 n p\right ) \int \frac{x^{-1+n}}{d+e x^n} \, dx}{3 g}-(e f g n p) \int \frac{x^{1+n}}{d+e x^n} \, dx-\frac{1}{3} \left (e g^2 n p\right ) \int \frac{x^{2+n}}{d+e x^n} \, dx\\ &=-\frac{e f^2 n p x^{1+n} \, _2F_1\left (1,1+\frac{1}{n};2+\frac{1}{n};-\frac{e x^n}{d}\right )}{d (1+n)}-\frac{e f g n p x^{2+n} \, _2F_1\left (1,\frac{2+n}{n};2 \left (1+\frac{1}{n}\right );-\frac{e x^n}{d}\right )}{d (2+n)}-\frac{e g^2 n p x^{3+n} \, _2F_1\left (1,\frac{3+n}{n};2+\frac{3}{n};-\frac{e x^n}{d}\right )}{3 d (3+n)}-\frac{f^3 p \log \left (d+e x^n\right )}{3 g}+\frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )}{3 g}\\ \end{align*}
Mathematica [A] time = 0.254249, size = 178, normalized size = 0.98 \[ \frac{(f+g x)^3 \log \left (c \left (d+e x^n\right )^p\right )-e n p \left (\frac{3 f^2 g x^{n+1} \, _2F_1\left (1,1+\frac{1}{n};2+\frac{1}{n};-\frac{e x^n}{d}\right )}{d (n+1)}+\frac{f^3 \log \left (d+e x^n\right )}{e n}+\frac{3 f g^2 x^{n+2} \, _2F_1\left (1,\frac{n+2}{n};2 \left (1+\frac{1}{n}\right );-\frac{e x^n}{d}\right )}{d (n+2)}+\frac{g^3 x^{n+3} \, _2F_1\left (1,\frac{n+3}{n};2+\frac{3}{n};-\frac{e x^n}{d}\right )}{d (n+3)}\right )}{3 g} \]
Antiderivative was successfully verified.
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Maple [F] time = 2.775, size = 0, normalized size = 0. \begin{align*} \int \left ( gx+f \right ) ^{2}\ln \left ( c \left ( d+e{x}^{n} \right ) ^{p} \right ) \, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{9} \,{\left (g^{2} n p - 3 \, g^{2} \log \left (c\right )\right )} x^{3} - \frac{1}{2} \,{\left (f g n p - 2 \, f g \log \left (c\right )\right )} x^{2} -{\left (f^{2} n p - f^{2} \log \left (c\right )\right )} x + \frac{1}{3} \,{\left (g^{2} x^{3} + 3 \, f g x^{2} + 3 \, f^{2} x\right )} \log \left ({\left (e x^{n} + d\right )}^{p}\right ) + \int \frac{d g^{2} n p x^{2} + 3 \, d f g n p x + 3 \, d f^{2} n p}{3 \,{\left (e x^{n} + d\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (g^{2} x^{2} + 2 \, f g x + f^{2}\right )} \log \left ({\left (e x^{n} + d\right )}^{p} c\right ), x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 120.028, size = 284, normalized size = 1.57 \begin{align*} f^{2} x \log{\left (c \left (d + e x^{n}\right )^{p} \right )} + \frac{f^{2} p x \Phi \left (\frac{d x^{- n} e^{i \pi }}{e}, 1, \frac{e^{i \pi }}{n}\right ) \Gamma \left (\frac{1}{n}\right )}{n \Gamma \left (1 + \frac{1}{n}\right )} + f g x^{2} \log{\left (c \left (d + e x^{n}\right )^{p} \right )} + \frac{g^{2} x^{3} \log{\left (c \left (d + e x^{n}\right )^{p} \right )}}{3} - \frac{e f g p x^{2} x^{n} \Phi \left (\frac{e x^{n} e^{i \pi }}{d}, 1, 1 + \frac{2}{n}\right ) \Gamma \left (1 + \frac{2}{n}\right )}{d \Gamma \left (2 + \frac{2}{n}\right )} - \frac{2 e f g p x^{2} x^{n} \Phi \left (\frac{e x^{n} e^{i \pi }}{d}, 1, 1 + \frac{2}{n}\right ) \Gamma \left (1 + \frac{2}{n}\right )}{d n \Gamma \left (2 + \frac{2}{n}\right )} - \frac{e g^{2} p x^{3} x^{n} \Phi \left (\frac{e x^{n} e^{i \pi }}{d}, 1, 1 + \frac{3}{n}\right ) \Gamma \left (1 + \frac{3}{n}\right )}{3 d \Gamma \left (2 + \frac{3}{n}\right )} - \frac{e g^{2} p x^{3} x^{n} \Phi \left (\frac{e x^{n} e^{i \pi }}{d}, 1, 1 + \frac{3}{n}\right ) \Gamma \left (1 + \frac{3}{n}\right )}{d n \Gamma \left (2 + \frac{3}{n}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (g x + f\right )}^{2} \log \left ({\left (e x^{n} + d\right )}^{p} c\right )\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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